Answer:
1.69515 seconds
Step-by-step explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration
![v^2-u^2=2as\\\Rightarrow s=(v^2-u^2)/(2a)\\\Rightarrow s=(0^2-33^2)/(2* -8.5)\\\Rightarrow s=64.06\ m](https://img.qammunity.org/2020/formulas/physics/college/ljq9kjrc6re8xgd79a88uzmav45v4ax8ik.png)
The distance between the traffic and the car after braking is 120-64.06 = 55.94 m
Time = Distance / Speed
![\text{Time}=(55.94)/(33)\\\Rightarrow \text{Time}=1.69515\ seconds](https://img.qammunity.org/2020/formulas/physics/college/ibw16vdu56kztmqqn71gl7ferukhe073wp.png)
The reaction time cannot be more than 1.69515 seconds