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What is the base 8 equivalent of 23 base 10?

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Converting a number
N from base 10 to any base
b is a matter of finding the largest powers of
b that
N contains. However many copies of this power of
b are needed is equal to the leading digit of
N in base
b. Then keep doing this with the remainder terms as needed.

In this case,

23 = 16 + 7 = 2*8^1 + 7

so the first digit of 23 in base 8 is 2. The remainder 7 contains no powers of 8, so we're done; the last digit is this remainder, and we write


23_(10)=27_8

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