Question

A professional golfer hits a golf ball of mass 46 g with her 5-iron, and the ball first strikes the ground 155 m away. The ball experiences a drag force of magnitude Fr = Cv^2 and has a terminal speed of 44.0 m/s. Calculate the drag constant C for the golf ball.

Answer 1

`C=2.32* 10^(-4)\ Ns^2/m^2`

Step-by-step explanation:

It is given that,

Mass of the golf ball, m = 46 g = 0.046 kg

Terminal speed of the ball, v = 44 m/s

The drag force,
`F_r=Cv^2`

Where, C is the drag coefficient. At terminal speed, the weight of the ball is balanced by the drag force.

`Cv^2=mg`

`C=(mg)/(v^2)`

`C=(0.046* 9.8)/((44)^2)`

`C=2.32* 10^(-4)\ Ns^2/m^2`

Hence, this is the required solution.