Question

Calculate the initial velocity of a baseball ball so you can make a home run. Assume the angle that the initial speed makes with the horizontal θ=29degrees.

Length of the baseball field is x=100m, height of fence is 3.5m.

Answer 1

Answer:35.13 m/s

Step-by-step explanation:

Given

launching angle
`=29^(\circ)`

Length of baseball field=100 m

height of fence=3.5 m

we know trajectory of projectile is given by

`y=xtan\theta -(gx^2)/(2u^2cos^\theta )`

where y=vertical distance

x=horizontal distance

u=initial velocity

`\theta`=launch angle

here y=3.5 m

x=100

`\theta =29^(\circ)`

`3.5=100* tan(29)-(9.8* 100^2)/(2u^2(cos29)^2)`

`(64121.0306)/(u^2)=100tan29-3.5`

`u^2=1234.7374`

u=35.13 m/s