Question

7. Assume you are dealing with a vertical walled reservoir having a surface area of 650,000 mwith an inflow of 0.5 m/s. How many hours will it take to raise the reservoir by 35 cm? (3 marks)

Answer 1

So reservoir will take 455000 sec to raise 35 cm

Step-by-step explanation:

We have given surface area of the reservoir = 650000
`m^2`

Rate of flow = 0.5 m/sec

Height through which reservoir is raise = 35 cm = 0.35 m

So volume
`\Delta V=surface\ area* height=650000* 0.35=227500m^3`

We have to calculate the time

Time is given by
`t=(\Delta V)/(rate\ pf\ flow)=(227500)/(0.5)=455000sec`