Answer:
b.
![16 \ m^(2)=19.13584 \ (y d)^(2) \approx \bold{20 \ (y d)^(2)}](https://img.qammunity.org/2020/formulas/mathematics/college/9hwj8et6oj15vtiw0jvuvdera8oce1nmiz.png)
Given:
16 square meters
Solution:
The square meter and the square yards conversion is:
![1 \ m^(2)=1.19599 \ (y d)^(2)](https://img.qammunity.org/2020/formulas/mathematics/college/j4sddmrnqjferdkebdti4qknxtcgn7qa92.png)
The “square meter” is the unit of the area which is equal to the square with the one meter as its side.
The “square yard” is also a unit of area which is equal to the square with the one yard as its side.
Now, from the question,
![\Rightarrow 16 * 1 \ m^(2)=16 * 1.19599 \ (y d)^(2)](https://img.qammunity.org/2020/formulas/mathematics/college/zj8pbk9kpll9si0qjbwqeu1bwhipop050a.png)
![\therefore 16 \ m^(2)=19.13584 \ (y d)^(2)](https://img.qammunity.org/2020/formulas/mathematics/college/2hphbpvm2r9sf2esf4efzfvnuiqcba0mu3.png)