Question

The magnitude of the electrostatic force between two identical ions that are separated by a distance of 8.3 × 10-10m is 192.9 × 10-9N.(a)What is the charge of each ion?(b)How many electrons are ""missing"" from each ion (thus giving the ion its charge imbalance)?

Answer 1

(a) 1.215 x 10^-13 J

(b) n = 7.6 x 10^5

Step-by-step explanation:

distance, r = 8.3 x 10^-10 m

Force, F = 192.9 x 10^-9 N

Let the charge is q.

(a) According to the Coulomb's law

`F=(Kq* q)/(r^(2))`

`192.9*10^(-9)=(9*10^(9)* q* q)/(\left (8.3* 10^(-10)  \right )^(2))`

q = 1.215 x 10^-13 C

(b) Let n number of electrons are missing.

`n = (q)/(e)=(1.215*10^(-13))/(1.6*10^(-19))`

n = 7.6 x 10^5