Question

Delay What is the required mass ratio to achieve an exhaust velocity of 2.455 km/s with a specific impulse of 294 seconds? Choose one. A. 2.34 B. 2.12 C.3.12 D.5.11 E. 4.33

Answer 1

Answer:

`(mo)/(mi) = 2.34`

Step-by-step explanation:

Given data:

exhaust velocity = 2.455 km/s

specific impulse = 294 second

`\Delta V = Ve ln(mo)/(mi)`

`\Delta v = velocity`

Ve = effective exhaust velocity

`Ve = Isp\time s g_0`

Isp specific impulse

g_o = standard gravity

`vE = 294 * 9.8 = 2881.2 m`

from above equation we have

`(mo)/(mi) = e^{(\Delta v)/(Ve)</p><p> [tex](mo)/(mi) = e^{(2455)/(2881.2)` [ 2.455 km/s = 2455 m/s]

`(mo)/(mi) = 2.34`