Answer:
The system
has infinitely many solutions

Explanation:
We have the following system of equations:

The augmented matrix of the system is:
![\left[\begin{array}c6&-5&7\\12&-10&14\end{array}\right]](https://img.qammunity.org/2020/formulas/mathematics/college/8n2ewm5jvbyu8xp2qfwuo7klvb67ki155s.png)
Transform the augmented matrix to the reduced row echelon form
- Row Operation 1: multiply the 1st row by 1/6
![\left[\begin{array}c1&-5/6&7/6\\12&-10&14\end{array}\right]](https://img.qammunity.org/2020/formulas/mathematics/college/7c6bn2h2ybd011y2gijzlo76633qdzc8yf.png)
- Row Operation 2: add -12 times the 1st row to the 2nd row
![\left[\begin{array}cc1&-5/6&7/6\\0&0&0\end{array}\right]](https://img.qammunity.org/2020/formulas/mathematics/college/doxlsoffm4eubdzbvfess89gw57qgnf8g7.png)
From the reduced row echelon form of the augmented matrix we have the corresponding system of linear equations:

The last row of the system (0 = 0) means that the system has infinitely many solutions.
