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A flowrate measuring device is installed in a horizontal pipe through which water is flowing. A U-tube manometer is connected to the pipe through pressure taps located 3 in. on either side of the device. The gage fluid in the manometer has a specific weight of 112 lb/ft3. Determine the differential reading of the manometer corresponding to a pressure drop between the taps of 0.5 lb/in2.

1 Answer

3 votes

Answer:

h=1.5 ft

Step-by-step explanation:

Specific weight for manometer


W=112\ lb/ft^3

Pressure drop between taps


\Delta P=0.5\ lb/in^2


\Delta P=0.5* 12^2\ lb/ft^2


\Delta P=72\ lb/ft^2

So


\Delta P=(\rho_m-\rho_w)gh


\Delta P=(W_m-W_w)h

We know that for water


W_w=64\ lb/ft^3

Now by putting the values


\Delta P=(W_m-W_w)h


72=(112-64)h

h=1.5 ft

So reading of manometer is 1.5 ft.

User Seth Duncan
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