Question

A flowrate measuring device is installed in a horizontal pipe through which water is flowing. A U-tube manometer is connected to the pipe through pressure taps located 3 in. on either side of the device. The gage fluid in the manometer has a specific weight of 112 lb/ft3. Determine the differential reading of the manometer corresponding to a pressure drop between the taps of 0.5 lb/in2.

Answer 1

h=1.5 ft

Step-by-step explanation:

Specific weight for manometer

`W=112\ lb/ft^3`

Pressure drop between taps

`\Delta P=0.5\ lb/in^2`

`\Delta P=0.5* 12^2\ lb/ft^2`

`\Delta P=72\ lb/ft^2`

So

`\Delta P=(\rho_m-\rho_w)gh`

`\Delta P=(W_m-W_w)h`

We know that for water

`W_w=64\ lb/ft^3`

Now by putting the values

`\Delta P=(W_m-W_w)h`

`72=(112-64)h`

h=1.5 ft

So reading of manometer is 1.5 ft.