Question

S = 1 / g t ² π, solve for t​

Answer 1

`\bf S=\cfrac{1}{2}gt^2\pi \implies S = \cfrac{gt^2\pi }{2}\implies 2S=gt^2\pi \implies \cfrac{2S}{g\pi }=t^2\implies \sqrt{\cfrac{2S}{g\pi }}=t`

Answer 2

`s = \frac{1}{g {t}^(2)\pi }`

multiply through by

`g {t}^(2) \pi`

`s * g {t}^(2) \pi = \frac{1}{g {t}^(2) \pi} * g {t}^(2) \pi`

`sg {t}^(2) \pi = 1`

dividing through by

sgπ

`{t}^(2) = (1)/(sg\pi)`

`t = \sqrt{ (1)/(sg\pi) }`