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X2+2x+8=0 solve by completing the square

User Malinda
by
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1 Answer

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Answer:

x = i sqrt(7) - 1 or x = -i sqrt(7) - 1

Explanation:

Solve for x:

x^2 + 2 x + 8 = 0

Subtract 8 from both sides:

x^2 + 2 x = -8

Add 1 to both sides:

x^2 + 2 x + 1 = -7

Write the left hand side as a square:

(x + 1)^2 = -7

Take the square root of both sides:

x + 1 = i sqrt(7) or x + 1 = -i sqrt(7)

Subtract 1 from both sides:

x = i sqrt(7) - 1 or x + 1 = -i sqrt(7)

Subtract 1 from both sides:

Answer: x = i sqrt(7) - 1 or x = -i sqrt(7) - 1

User Gary Qian
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