Question

Find the numeral preceding and succeeding each of the following numerals. a. 100eight b. 10000five c. 101two

Answer 1

Answer and Solution:

For:

(a)
`(100)_(8)`

Now,

`(100)_(8) = (2^(8))_(10) = (64)_(10)`

Therefore, the no. preceding is
`(63)_(10) = (77)_(8)`

The no. succeeding is
`(65)_(10) = (101)_(8)`

(b)
`(10000)_(5)`

Now,

`5^(4) = (625)_(10)`

Therefore, the no. preceding is
`(624)_(10) = (4444)_(5)`

The no. succeeding is
`(626)_(10) = (10001)_(5)`

(c)
`(101)_(2)`

Now,

`(101)_(2) = 2^(2)* 1 + 0* 2 + 2^(0)* 1 = (5)_(10)`

Therefore, the no. preceding is
`(4)_(10) = (100)_(2)`

The no. succeeding is
`(6)_(10) = (110)_(2)`