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Constructive proof: There exists an integer x such that: (x^3)/5 > x^2

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Answer:


x>5

Explanation:

We are asked to find an integer x such that
(x^3)/(5)>x^2.

First of all, we will multiply both sides of inequality by 5.


(x^3)/(5)>x^2


(x^3)/(5)*5>5*x^2


x^3>5x^2

Divide both sides by
x^2:


(x^3)/(x^2)>(5x^2)/(x^2)


x>5

Therefore, the value of x is any number greater than 5.

User Dodrg
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