2 Answers

Steve Knight · Answer 1 · 2020-08-29T14:23:20+0000

Answer:

$\bold{(11 x-2)\left(121 x^(2)+22 x+4\right)}$

1331 x^(3)-8

In this problem, we need to find the factors of the given expression.

The factors of a given number/expression are the numbers/expressions which results in given number on multiplying.

The given expression is in an algebraic expression which is:

x^(3)-y^(3)=1331 x^(3)-8

On giving the cube forms,

$\Rightarrow x^(3)-y^(3)=(11 x)^(3)-(2)^(3)$

Now, the factored form of the above expression is:

$x^(3)-y^(3)=(x-y)\left(x^(2)+x y+y^(2)\right)$

Now,

$\therefore(11 x)^(3)-(2)^(3)=(11 x-2)\left(121 x^(2)+22 x+4\right)$

The above given is the factor for the given difference in the cube.