Answer:
the quality of the refrigerant exiting the expansion valve is 0.2337 = 23.37 %
Step-by-step explanation:
given data
pressure p1 = 1.4 MPa = 14 bar
temperature t1 = 32°C
exit pressure = 0.08 MPa = 0.8 bar
to find out
the quality of the refrigerant exiting the expansion valve
solution
we know here refrigerant undergoes at throtting process so
h1 = h2
so by table A 14 at p1 = 14 bar
t1 ≤ Tsat
so we use equation here that is
h1 = hf(t1) = 332.17 kJ/kg
this value we get from table A13
so as h1 = h2
h1 = h(f2) + x(2) * h(fg2)
so
exit quality =
![(h1 - h(f2))/(h(fg2))](https://img.qammunity.org/2020/formulas/engineering/college/2tdhjqnjepn9jolucxthrd7s3tr73g12kl.png)
exit quality =
![(332.17- 9.04)/(1382.73))](https://img.qammunity.org/2020/formulas/engineering/college/458h3y4uk5u7thp0y447lxvupyt3ud0b8c.png)
so exit quality = 0.2337 = 23.37 %
the quality of the refrigerant exiting the expansion valve is 0.2337 = 23.37 %