Question

Please help Asap!

Solve for x and show your steps. Is the solution extraneous? Check your work to show how you determined if the solution is extraneous or not.

The square root of the quantity 11 x plus 5 end quantity equals 7.

Answer 1

Answer: x =4, not extraneous.

Step-by-step explanation:

`√(11x + 5) = 7`, square all sides.

Because the square root is squared, it is reversed:
`11x+5 =7^(2)`

(72 = 49)

Subtract 5 from all sides: 11x = 44

(49 - 5 = 44)

(11x is an unknown so we cannot subtract 5 from it)

To get rid of the unknown, divide 11 on all sides: x = 4

(11x ÷ 11 = 1, x is written as one) (44 ÷ 11 = 4)

x = 4

The solution is not extraneous.

Answer 2

Answer:

Step-by-step explanation:

\sqrt{11x+5}

11x+5

= 7 ( square both sides )

11x + 5 = 7² = 49 ( subtract 5 from both sides )

11x = 44 ( divide both sides by 11 )

x = 4

substitute x = 4 into the left side of the equation and if equal to the right side , then it is the solution.

\sqrt{11(4)+5}

11(4)+5

= \sqrt{44+5}

44+5

= \sqrt{49}

49

= 7 ← equals right side

then x = 4 is the solution