Answer:
pH is 3,81
Step-by-step explanation:
The equilibrium:
Succinic acid ⇄ Succinate + H⁺; ka = 6,17x10⁻⁵
The initial moles of each compound are:
Succinic acid: 0,350L × 0,500M = 0,175 moles
Succinate: 0,350L × 0,200M = 0,07 moles
The addition of HCl will consume succinate and produce succinic acid, thus:
Moles of HCl:
0,0012L × 0,01M = 1,2x10⁻⁵ moles
Succinic acid: 0,175 moles + 1,2x10⁻⁵ moles = 0,175012 moles
Succinate: 0,07 moles - 1,2x10⁻⁵ moles = 0,069988 moles
The equilibrium equation is:
ka =
![([succinate][H^(+)])/([Succinic Acid])](https://img.qammunity.org/2020/formulas/chemistry/college/h4jqofj2180bn0qaprca5925aftcjelwog.png)
Replacing:
6,17x10⁻⁵ =
![([0,069988][H^(+)])/([0,175012])](https://img.qammunity.org/2020/formulas/chemistry/college/rarkrmxgccqk1fng2brkdw79oeb5hzx642.png)
Solving:
[H⁺] = 1,543x10⁻⁴
As pH = -log [H⁺]
pH = 3,81
I hope it helps!