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Synthesis gas consists of a mixture of H2 and CO. Calculate at 101kpa is compressed at constant temperature from 7.20 dm3 to 4.21 dm3. calculate the final pressure of the gas

2 Answers

6 votes

Step-by-step explanation:

According to Boyle's law, volume of a gas is inversely proportional to its pressure at a constant temperature.

Mathematically,
P \propto (1)/(V); at constant T

It is given that,


P_(1) = 101 kPa,
P_(2) = ?


V_(1) = 7.20 dm^(3),
V_(2) = 4.21 dm^(3)

We will calculate the final pressure as follows.


P_(1)V_(1) = P_(2)V_(2)


101 kPa * 7.20 dm^(3) = P_(2) * 4.21 dm^(3)


P_(2) = (101 kPA * 7.20 dm^(3))/(4.21 dm^(3))

= 172.73 kPa

Thus, we can conclude that the final pressure of the gas is 172.73 kPa.

User Gaurang
by
6.2k points
3 votes

Answer:

The final pressure is 173 kPa.

Step-by-step explanation:

A mixture of gases at an initial pressure of P₁ = 101 kPa is compressed from an initial volume V₁ = 7.20 dm³ to a final volume V₂ = 4.21 dm³. If we suppose an ideal gas behavior and that temperature remains constant, we can apply Boyle's law to find out the final pressure P₂:

P₁ . V₁ = P₂ . V₂


P_(2)=(P_(1).V_(1))/(V_(2))=(101kPa.7.20dm^(3) )/(4.21dm^(3) )  =173kPa

User Makenshi
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6.3k points