Answer: The mass of water produced is 1.8 grams
Step-by-step explanation:
To calculate the number of moles, we use the equation:
.....(1)
Given mass of ethanol = 4.59 g
Molar mass of ethanol = 46.07 g/mol
Putting values in equation 1, we get:

The chemical equation for the reaction of ethanol with oxygen gas follows:

By Stoichiometry of the reaction;
1 mole of ethanol produces 1 mole of water.
So, 0.0996 moles of ethanol will produce =
of water.
Now, calculating the mass of water from equation 1, we get:
Molar mass of water = 18 g/mol
Moles of water = 0.0996 moles
Putting values in equation 1, we get:

Hence, the mass of water produced is 1.8 grams