Question

Show the calculation of the mass (grams) of a 14.5 liter gas sample with a molecular weight of 82 when collected at 29°C and 740 mm

Answer 1

In this conditions, the gaswll weight 46.74 g.

Step-by-step explanation:

The idal gas law states that:

PV = nRT,

P: pressure = 740 mmHg = 0.97 atm

V: volume = 14.5 L

n: number of moles

R: gas constant =0.08205 L.atm/mol.K

T: temperature = 29°C = 302.15K

`n = (PV)/(RT) \\n = (0.97x14.5)/(0.082 x 302.15 ) \\n = 0.57 mol`

1 mol gas ___ 82 g

0.57 mol gas __ x

x = 46.74 g