Question

The steps required to prepare 200.0 mL of an aqueous solution of iron (III) chloride, at a concentration of 1.25x10^-2 M. Please show the calculations determining what mass of solute to use in making this solution.

Answer 1

In order to prepare 200.0 mL of an aqueous solution of iron (III) chloride, at a concentration of 1.25 x 10⁻² M, you need to weight 0.4055 g of FeCl₃ and add to 200.0 mL of water.

Step-by-step explanation:

Concentration: 1.25 x 10⁻² M

1,25 x 10⁻² mol FeCl₃ ___ 1000 mL

x ___ 200.0 mL

x = 2.5 x 10⁻³ mol FeCl₃

Mass of FeCl₃:

1 mol FeCl₃ _____________ 162.2 g

2.5 x 10⁻³ mol FeCl₃ _______ y

y = 0.4055 g FeCl₃