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Blood Alcohol Content (BAC) is sometimes reported in weight-volume percent and, when it is, a BAC of 0.10% corresponds to 0.10 g ethyl alcohol per 100 ml of blood. In many jurisdictions, a person is considered legally intoxicated if his or her BAC is 0.10%. Suppose that a 68 kg person has a total blood volume of 5.4 L and breaks down ethyl alcohol at a rate of 10.0 grams per hour. How many145 ml glasses of wine, consumed over three hours, will produce a BAC of 0.10% in his 68 kg person?

1 Answer

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Answer:

2,3 glasses of wine.

Step-by-step explanation:

In three hours, to produce a BAC of 0,10% for a 68kg person (5,4L blood) you need to consume:


(0,10 gEthylAlcohol)/(100mL blood) * 5400mLBlood+10,0g/h*3h = 30,54g of ethyl alcohol

Assuming a 11,6% (v/v) of wine Where density of ethyl alcohol is 0,789 g/mL:


30,54gEthylAlcohol*(1mL ethanol)/(0,789g) (100mLwine)/(11,6 mL ethanol)
= 333,7 mL wine

Thus, the person need to consume:


(333,7 mL wine)/(145mL) = 2,3 glasses of wine

User Veerendra Gadekar
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