Question

What is the percentage of s-character in an sp hybrid? O 25% 50% o 75% O 66%

Answer 1

Answer: 50%

Explanation:

The number of electron pairs are 2 for hybridization to be
`sp` and the electronic geometry of the molecule will be linear.

1. percentage of s character in sp hybrid orbital =
`\frac{\text {number of s orbitals}}{\text {total number of orbitals}}=(1)/(2)* 100=50\%`

2. percentage of s character in
`sp^2` hybrid orbital =
`\frac{\text {number of s orbitals}}{\text {total number of orbitals}}=(1)/(3)* 100=33.3\%`

3. percentage of s character in
`sp^3` hybrid orbital =
`\frac{\text {number of s orbitals}}{\text {total number of orbitals}}=(1)/(4)* 100=25\%`

Thus percentage of s-character in an sp hybrid is 50%.