Answer:
2.5 grams of of water is consumed by the reaction of 6.2 g of carbon dioxide.
Step-by-step explanation:
![6H_2O+6CO_2\rightarrow C_6H_(12)O_6+6O_2](https://img.qammunity.org/2020/formulas/chemistry/college/bdt0o9do7v5qe2jnr15vq485pckcsu5riu.png)
Moles of carbon dioxide =
![(6.2 g)/(44 g/mol)=0.1410 mol](https://img.qammunity.org/2020/formulas/chemistry/college/tbbapvmj48ei7xmsu0jqvi53nitr1tjfae.png)
According to reaction , 6 moles of carbon dioxide reacts with 6 moles of water.
Then 0.1410 moles of carbon dioxide will react with:
of water.
Mass of 0.14109 moles of water = 0.1410 mol × 18 g/mol = 2.536 g ≈ 2.5 g
2.5 grams of of water is consumed by the reaction of 6.2 g of carbon dioxide.