Question

Using the quadratic formula to solve x2 + 20 = 2x. what are the values of x?

Answer 1

Answer: The answer is x=1±i√19

Answer 2

`1\pm √(19)i`

Explanation:

To solve :
`x^2-2x+20=0`

Quadratic Formula :

For quadratic equation of form
`ax^2+bx+c=0`, roots are given by

`x=(-b\pm √(b^2-4ac))/(2a)`

On comparing equation
`x^2-2x+20=0` with equation
`ax^2+bx+c=0`, we get
`a=1\,,\,b=-2\,,\,c=20`

Also, we know that
`√(-1)=i`

So,

`x=(2\pm √(4-80))/(2)=(2\pm √(-76))/(2)=(2\pm 2√(19)i)/(2)=1\pm √(19)i`