Question

Pls help!! it’s due soon!

•how long would it take a runner to travel 1500m if they were traveling at 6m/s?

•If a car drives at 18m/s for 25 seconds how far has it traveled?

•if it takes a car 60 seconds to travel 5 meters how fast was the car traveling?

Answer 1

1.) 250 seconds

2.) 450 meters

3.) 0.083 m/s

Step-by-step explanation:

Formula

`\displaystyle{1.) \ v = (s)/(t)}\\\\\displaystyle{2.) \ s = vt}\\\\\displaystyle{3.) \ t = (s)/(v)}`

Where:

• s = distance
• v = speed
• t = time

First formula is used if you want to find the speed; second formula is used if you want to find distance; the third formula is used if you want to find time.

First Question

For your first question, since it asks you for how long, we will be using the formula that finds the time which is the third formula:

`\displaystyle{ t = (s)/(v)}`

We know that distance (s) is 1500 meters and speed (v) is 6 m/s. Substitute s = 1500 and v = 6 in the formula:

`\displaystyle{ t = \frac{1500 \ \, \sf{m}}{6 \ \, \sf{m/s}}}\\\\\displaystyle{ t = 1500 \ \, \sf{m} \ / \ 6 \ \, \sf{(m)/(s)}}\\\\\displaystyle{ t = 1500 \ \, \sf{m} \ * \ \, \sf{(s)/(6m)}}\\\\\displaystyle{ t = 250 \ \, \sf{s}}`

Therefore, it will take 250 seconds to reach 1500 meters if they travel at rate of 6 m/s.

Second Question

For this question, it asks how far, so we will be using the distance formula which is the second formula:

`\displaystyle{s = vt}`

We know that speed (v) is 18 m/s and time (t) is 25 seconds. Substitute v = 18 and t = 25 in the formula:

`\displaystyle{s = 18 \ \, \sf{(m)/(s)} \ * \ 25 \ \, \sf{s}}\\\\\displaystyle{s = 18 \ \, \sf{m} * 25}\\\\\displaystyle{s = 450 \ \, \sf{m}}`

Therefore, the car will travel 450 meters.

Third Question

For this question, it asks about how fast which is related to speed. Therefore, we will be using speed formula which is first equation:

`\displaystyle{v = (s)/(t)}`

We know that distance (s) is 5 meters and time (t) is 60 seconds. Therefore, substitute s = 5 and t = 60 in the formula:

`\displaystyle{v = \frac{5 \ \, \sf{m}}{60 \ \, \sf{s}}}\\\\\displaystyle{v = \frac{1 \ \, \sf{m}}{12 \ \, \sf{s}}}`

Therefore, the car will travel at rate of 1/12 m/s or 0.083 m/s