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Sabrina is planning a 1830-mile driving trip. Her car gets an average of 24 mpg, and the cost of gas is about $4.09/gallon. What is the approximate driving cost of the trip?

A)$304
B)$312
C)$318
D)$328

User Lounges
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2 Answers

6 votes
The closest answer is B)$312.
To find this answer, you know that she is driving 1830 miles. If she can drive 24 miles with one gallon, that means she will need 76.25 gallons to complete the trip. If the cost of one gallon is $4.09, then you multiply the number of gallons (76.25) by the price (4.09) to get an answer of 311.8625. Rounded to the nearest whole number, the answer is $312.
User Kaa
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6.9k points
3 votes

Answer:

Option B. $312

Explanation:

Sabrina is planning a 1830 mile driving trip.

First we calculate the amount of gasoline would use in the trip.

∵ the mileage of her car = 24 miles/gallon

∴ for 1830 miles gasoline would be needed =
(1830)/(24)

= 76.25 gallons

∵ the cost of 1 gallon gas = $4.09

∴ the cost of 76.25 gallons of gasoline = 76.25 × 4.09

= $311.86 ≈ $312

The approximate driving cost of the trip would be $312.

User Hrk
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