Answer:
The factored form of
![16x^(2) - 16x - 12 \text { is } 4(2x - 3)(2x + 1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/8ayxzu165tze3gd22tq7xwz5orn6r5lxd0.png)
Solution:
From question, given that
![16x^(2)-16x-12](https://img.qammunity.org/2020/formulas/mathematics/middle-school/1gu473a0cgdugtrnxlnz9kn5dzbfd6uadu.png)
To factorize the given expression, follow the below steps:
---- eqn 1
Taking 4 as a common term in equation 1, we get
![=4\left(4 x^(2)-4 x-3\right)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/cc4tauzu7upbet1zixsbwjbmds04wt2xp5.png)
“4x” can be rewritten as –6x+2x. Now the above equation becomes,
![=4\left(4 x^(2)-6 x+2 x-3\right)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/nfx2jb1md5gy9qa0ogwvjzn7x7gyuplpqs.png)
By taking 2x as common from
, the above equation becomes,
![=4[2x(2 x-3)+1(2 x-3)]](https://img.qammunity.org/2020/formulas/mathematics/middle-school/s4f0jyz36yj1egm7vwd0pr5u8ih8974dup.png)
![=4(2 x-3)(2 x+1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/id2y3mkq5khkbztf8n6jgcivx7pb4wp77s.png)
Hence the factor of
![16 x^(2)-16 x-12 \text { is } 4(2 x-3)(2 x+1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/4nlqlqieq6138qwcf8slk3v4tcxfmd5zrn.png)