Question

Each shot of the laser gun most favored by Rosa the Closer, the intrepid vigilante of the lawless 22nd century, is powered by the discharge of a 1.35 F capacitor charged to 53.9 kV . Rosa rightly reckons that she can enhance the effect of each laser pulse by increasing the electric potential energy of the charged capacitor. She could do this by replacing the capacitor's filling, whose dielectric constant is 435 , with one possessing a dielectric constant of 901 . Find the electric potential energy of the original capacitor when it is charged. original capacitor potential energy: J

Answer 1

`E=1/2*C*V^2=0.5*1.35*(53.9*10^3)^2=1.96*10^9J`

Step-by-step explanation:

Electrical potential energy of a capacitor with capacitance, C, and Voltage, V, is:

`E=1/2*C*V^2`

The original capacitor has a capacitance of 1.35F and a voltage of 53.9kV.

`E=1/2*C*V^2=0.5*1.35*(53.9*10^3)^2=1.96*10^9J`