Question

Y=x² – 8x + 16

So right now I'm trying to figure out the inverse relation ​

Answer 1

The inverse relation is:

`y=4 \pm √(x)`

Explanation:

We need to solve for x.

Useful formula: (x-y)^2=x^2-2xy+y^2.

`y=x^2-8x+16`

`y=(x-4)^2`

Now, take the square root of both sides:

`\pm √(y)=x-4`

Add 4 on both sides:

`4 \pm √(y)=x`

Interchange x and y:

`4 \pm √(x)=y`

The inverse relation is:

`y=4 \pm √(x)`