Question

Choose the inverse of y=x^2-10x

Answer 1

its d on edg

Explanation:

Answer 2

Inverse of
`\bold{y=x^(2)-10 x}` is
`\bold{y=5 \pm √(x+25)}`

Solution:

Given that

`y=x^(2)-10 x`

Adding
`5^(2)` on both sides

`y+5^(2)=x^(2)-10 x+5^(2)`

Rewrite 10x as 2(5)x,

`y+5^(2)=x^(2)-2(5) x+5^(2)`

By using
`\left(a-b)^(2)=a^(2)-2 a b+b^(2)\right` , we get

`y+5^(2)=(x-5)^(2)`

`y+25=(x-5)^(2)` (Completing the square)

Now swap x and y, we get

`x+25=(y-5)^(2)`

Rewrite the above equation,

`(y-5)^(2)=x+25`

Taking square root of both sides,

`y-5=\pm √(x+25)`

Adding 5 on both sides,

`y=5 \pm √(x+25)`

Hence inverse of
`\bold{y=x^(2)-10 x \text { is } y=5 \pm √(x+25)}`