Question

a 1150 kg car is on a 8.70 hill. using x-y axis tilted down the plane, what is the x-component of the normal force(unit=N)

Answer 1

The answer is actually zero

Step-by-step explanation:

put in the box 0

Answer 2

The x-component of the normal force is equal to 1706.45 N.

Why?

To solve the problem, and since there is no additional information, we can safely assume that the x-axis is parallalel to the hill surface and the y-axis is perpendicular to the x-axis. Knowing that, we can calculate the components of the normal force (or weight for this case), using the following formulas:

`N_(x)=W*Sin(\alpha)=mg*Sin(\alpha)\\\\N_(y)=W*Cos(\alpha)=mg*Cos(\alpha)`

Now, using the given information, we have:

`mass=m=1150Kg\\\alpha=8.70\°\\g=9.81(m)/(s^(2))`

Calculating, we have:

`N_(x)=mg*Sin(\alpha)`

`N_(x)=1150Kg*9.81(m)/(s^(2))*Sin(8.70\°)\\\\N_(x)=11281.5(Kg.m)/(s^(2) )*Sin(8.70\°)=1706.45(Kg.m)/(s^(2) )=1706.45.23N`

Hence, we have that the x-component of the normal force is equal to 1706.45 N.

Have a nice day!