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The trace of a square n x n matrix A = (a_ij) is the sum a11 + a22 +...+ ann of the entries on its main diagonal.Let V be the vector space of all 2 x 2 matrices with real entries. Let H be the set of all 2 x 2 matrices with real entries that have trace 0. Is H a subspace of the vector space V?Is H closed under addition? If it is, enter CLOSED. If it is not, enter two matrices in H whose sum is not in H, using a comma separated list and syntax such as [[????,????],[????,????]], [[????,????],[????,????]] for the answer [1324],[5768]. (Hint: to show that H is not closed under addition, it is sufficient to find two idempotent matrices ???? and ???? such that (????+????)2≠(????+????).)

User Hichem
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3 votes

Answer:

Subspace; Closed

Explanation:

The trace of a square n x n matrix
A = (a_(ij)) is the sum
a_(11) + a_(22) +...+ a_(nn) of the entries on its main diagonal.

Let V be the vector space of all 2 x 2 matrices with real entries.

Let H be the set of all 2 x 2 matrices with real entries that have trace 0.

Theorem: H is a subspace of the vector space V, if

1) for every
A,\ B\in H: \ \ A+B\in H;

2) for each
A\in H and
\lambda \in R:\ \ \lambda A\in H.

Check these two conditions:

1) Let
A=(a_(ij)),\ B=(b_(ij))\in H

This means


a_(11)+a_(22)=0\\ \\b_(11)+b_(22)=0

Consider the matrix
A+B=(a_(ij)+b_(ij))=\left(\begin{array}{cc}a_(11)+b_(11)&a_(12)+b_(12)\\a_(21)+b_(21)&a_(22)+b_(22)\end{array}\right)

This matrix sum has the trace


(a_(11)+b_(11))+(a_(22)+b_(22))=(a_(11)+a_(22))+(b_(11)+b_(22))=0+0=0

So,
A+B\in H

2) Consider
\lambda A=\lambda\left(\begin{array}{cc}a_(11)&a_(12)\\a_(21)&a_(22)\end{array}\right)=\left(\begin{array}{cc}\lambda a_(11)&\lambda a_(12)\\\lambda a_(21)&\lambda a_(22)\end{array}\right)

Its trace is
\lambda a_(11)+\lambda a_(22)=\lambda (a_(11)+a_(22))=\lambda \cdot 0=0

So,
\lambda A\in H

Therefore, H is a subspace of the vector space V and is closed under addition.

User Zilla
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