Question

What is the solution of the equation when solves over the complex numbers?
x^2+20=0

Answer 1

x = ± 2i
`√(5)`

Explanation:

Given

x² + 20 = 0 ( subtract 20 from both sides )

x² = - 20 ( take the square root of both sides )

x = ±
`√(-20)`

= ±
`√(4(5)(-1))`

= ± [
`√(4)` ×
`√(5)` ×
`√(-1)` ]

= ± 2i
`√(5)`

Answer 2

(x=2i√5)(x=-2√5)