Step-by-step explanation:
Let the molar mass of KBr is
and NaBr is
.
In 21.545 g, the moles of KBr and NaBr are
and
.
Therefore,
= 21.545 g

Mass of AgBr is 35.593 g.
= 35.593 g
= 35.593 g
= 35.593 g

Now, putting the given values into the above formula as follows.


=

=

= 0.224 mol
Hence, mass of KBr will be calculated as follows.

= 26.656 g
Thus, we can conclude that mass of KBr present in the original mixture is 26.656 g.