Question

The decomposition of NOBr is studied manometrically because the number of moles of gas changes; it cannot be studied colorimetrically because both NOBr and Br2 are reddish-brown. 2NOBr(g) →2NO(g) + Br2(g) Use the data below to make the following determinations: (a) the average rate of decomposition of NOBr over the entire experiment. (b) the average rate of decomposition of NOBr between 2.00 and 4.00 seconds. Time (s) [NOBr] (mol/L)0.00 0.01002.00 0.00714.00 0.00556.00 0.00458.00 0.003810.00 0.0033The rates of decomposition of NOBr are

Answer 1

a) 6,7x10⁻⁴M/s

b) 8,0x10⁻⁴M/s

Step-by-step explanation:

a) You can determine the average rate of descomposition calculating the ratio of change of concentration to change of time.

For the entire experiment:

t=0,00→ 0,0100M

t=10,00→0,0033M

`(0,0100M-0,0033M)/(10,00s-0,00s)` = 6,7x10⁻⁴M/s

b) Between 2,00 and 4,00 seconds:

t=2,00→ 0,0071M

t=4,00→0,0055M

`(0,0071M-0,0055M)/(4,00s-2,00s)` = 8,0x10⁻⁴M/s

I hope it helps!