Question

Erfan pushes a 5kg crate of stage props starting from rest alongthe smooth and slippery horizontal floor of a theater stage. Thecrate moves with a constant acceleration for 10 seconds as Erfanpushes with a force of 0.22 N to reach the edge of the stage. Thenthe crate runs off the edge of the stage and lands in the orchestrapit below. The floor of the orchestra pit is 3 meters below theedge of the stage. Assume friction is negligible. How far awayfrom the stage edge does the crate land?

Answer 1

`d = 0.344 m`

Step-by-step explanation:

mass of the crate = 5 kg

Force on crate = 0.22 N

`acceleration = (Force)/(mass)`

`acceleration = (0.22)/(5)`

`a = 0.044 m/s^2`

now the speed of the crate after t = 10 s

`v_f = v_i + at`

`v_f = 0 + 0.044 * 10`

`v_f = 0.44 m/s`

Now the time taken by the crate to reach the orchestra pit

`y = (1)/(2)gt^2`

`3 = (1)/(2)(9.8)t^2`

`t = 0.78 s`

now we know that

`d = vt`

`d = (0.44)(0.78)`

`d = 0.344 m`