Answer:
The probabability is

Explanation:
We are going to suppose that each score has the same probability.
For example :

Where P(66) is the probability of score a 66 and P(89) is the probability of score an 89
If A is a certain score :

In the exercise :

Bart must score higher than an 85 on the final exam.
We are looking for the probability of the event : ''Bart obtains a 1 or a 2 or ... or a 85''
This can be written in terms of events as :
P(1∪2∪...∪85) = P(1) + P(2) + ... + P(85)
As we consider each event as independent
