Question

Pumpkin Toss In Denver, children bring their old jack-o-lanterns

to the top of a tower and compete for accuracy in hitting a target on the ground (FIGURE 4-21). Suppose that the tower is 9.0 m high and that the bull's-eye is a horizontal distance of 3.5 m
from the
launch point. If the pumpkin is thrown horizontally, what is the
launch speed needed to hit the bull's-eye?

Answer 1

launch speed = v = 2.57 m/s

Step-by-step explanation:

This problem is related to projectile motion. To find the launching speed of pumpkin, we first have to find the time of flight, then using R = vt, We can find launching speed of pumpkin.

Given data:

Height = h = 9.0 m

Horizontal distance = R = 3.5 m

Velocity = v = ?

As the pumpkin is thrown horizontally, So Initial vertical velocity of pumpkin is zero, So we can use 2nd equation of motion to find time of flight.

Using 2nd equationof motion

`h = v_{i_(y)}t + (1)/(2)gt^(2)`

`v_{i_(y)}` = 0

So,

`h=(1)/(2)gt^(2)`

`9=(1)/(2)(9.8)t^(2)`

t = 1.36 s

Using R = vt

v = R/t

v = 3.5/1.36

v = 2.57 m/s