Question

The density of oxygen gas is 1.429 × 10–3 g/cm3 at standard conditions. What would be the percent error of the average of two separate experimental determinations measuring 1.112 × 10–3 g/cm3 and 1.069 × 10–3 g/cm3? (To solve this problem, average the two readings before calculating the percent error.)

Answer 1

0.034%

Step-by-step explanation:

First, let's calculated the average density (da) of the two experimental, which the sum of them divided by 2:

`da = (1.112x10^(-3) + 1.069x10^(-3))/(2)`

da = 1.090x10⁻³ g/cm³

The relative error is given by the difference of the correct value and the avarege, divided by the correct value:

`e = (1.429x10^(-3) - 1.090x10^(-3))/(1.429x10^(-3))`

e = 3.39x10⁻⁴ x 100%

e = 0.034%