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Two tiny metal spheres A and B, mass mA = 5.00 g and mB = 10.0 g, have equal positive charge q = 5.00 μC. The spheres are connected by a massless nonconducting string of length d = 1.00 m, which is much greater than the radii of the spheres.

a. What is the electric potential energy of the system?

User Maricruz
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1 Answer

5 votes

Answer:

U=0.22475 Joules

Step-by-step explanation:

The electric potential energy between 2 charges can be calculated with the formula
U=k(q_1q_2)/(r), where (in S.I.):


k=8.99*10^(9) Nm^(2)C^(-2) is the Coulomb constant


q_1=q_2=5.00*10^(-6)C are the values of the charges


r=1.00m their separation

So we have
U=k(q_1q_2)/(r)=0.22475J

User Sjeijoet
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