Answer:
q = - 93.334 nC
Step-by-step explanation:
GIVEN DATA:
Radius of ring 73 cm
charge on ring 610 nC
ELECTRIC FIELD p FROM CENTRE IS AT 70 CM
E = 2000 N/C
Electric field due tor ring is guiven as
![E = (KQx)/([x^2+ R^2]^(3/2))](https://img.qammunity.org/2020/formulas/physics/high-school/ngj9vu6zblhveo32gmc9kpyl4bmsmezo9k.png)

E1 = 3714.672 N/C
electric field due to point charge q



now the eelctric charge at point P is
E = E1 + E2

solving for q
q = - 93.334 nC