Question

Two forces act on an object. The first force has a magnitude of 15.0 N15.0 N and is oriented 58.0°58.0° counterclockwise from the +x+x ‑axis, whereas the second force has xx ‑ and yy ‑components (−19.0 N,18.5 N).(−19.0 N,18.5 N). Express the magnitude and direction of the net force.

Answer 1

F = 33.12 N

Step-by-step explanation:

given,

first force = 15 N is oriented at 58.0° counterclockwise

second force = (−19.0 N,18.5 N)

x-component of first force = 15 cos 58.0° = 7.95 N

y-component of second force = 15 sin 58.0° = 12.72 N

second component

now,

F netx = 7.95 - 19 = -11.05 N

F nety = 12.72 + 18.5 = 31.22 N

`F=√((-11.05)^2+31.22^2)`

F = 33.12 N

`tan \theta = -(31.22)/(11.05)`

θ = -70.51°