Question

A light, inextensible cord passes over a light, frictionless pulley with a radius of 15 cm. It has a(n) 14 kg mass on the left and a(n) 5.2 kg mass on the right, both hanging freely. Initially their center of masses are a vertical distance 2.5 m apart. The acceleration of gravity is 9.8 m/s 2 .

Answer 1

The rate of acceleration is 7.441 m/s/s.

(19 - 2.6) * 9.8 / (19 + 2.6) = 7.441

The tension in the cord is 44.826 Newtons.

2.6 * (9.8 + 7.441) = 44.826

or

19 * (9.8 - 7.441) = 44.826

Step-by-step explanation:

Answer 2

Answer with Explanation:

We are given that

`m_1=14 kg`

`m_2=5.2 lg`

Vertical distance,d=2.5 m

Acceleration due to gravity=
`g=9.8 m/s^2`

a.Acceleration=
`a=((m_1-m_2))/(m_1+m_2)g`

Substitute the values

Acceleration, a=
`(14-5.2)/(14+5.2)* 9.8`

Acceleration, a=
`4.49 m/s^2`

b.Tension in the cord,
`T=m_2(a+g)`

Tension in the cord,
`T=5.2(9.8+4.49)=74.3 N`

Hence, the tension in the cord=74.3 N