Question

When jeff ran up a hill at 7.0m/s the horizontal component of velocity vector was 5.1m/s

Answer 1

Answer: 4.8 m/s

Step-by-step explanation:

The complete question is written below:

Jeff ran up the hill at 7.0 m/s. The horizontal component of Jeff's velocity vector was 5.1 m/s. What was the vertical component of Jeff's velocity?

We have the following data:

Jeff's velocity:
`V=7 m/s`

Horizontal component of Jeff's velocity vector:
`V_(x)=5.1 m/s`

We need to find the vertical component of Jeff's velocity vector
`V_(y)`

If we observe the figure attached, both components of Jeff's velocity vector and the vector itself, form a right triangle where
`V` is the hypotenuse. Hence, we can use the pithagoream theorem to find
`V_(y)`:

`V^(2)={V_(x)}^(2) +{V_(y)}^(2)`

Finding
`V_(y)`:

`V_(y)=\sqrt{V^(2)-{V_(x)}^(2)`

`V_(y)=\sqrt{(7 m/s)^(2)-{(5.1 m/s)}^(2)`

Finally:

`V_(y)=4.79 m/s \approx 4.8 m/s`