Question

A 40 kg skier skis directly down a frictionless slope angled at l-0o to the horizontal. Assume the skier moves in the negative direction of an x axis along the slope.A wind force with component F, acts on the skier. What is F" if the magnitude of the skier's velocity is (a) constant, (b) increasing at a rate of 1.0 m/s2, and (c) increasing at arate of 2.0 mlsz?

Answer 1

The wind force component F is zero when the magnitude of the skier's velocity is constant. When the magnitude of the skier's velocity is increasing at a rate of 1.0 m/s^2 or 2.0 m/s^2, the wind force component F is 40 N and 80 N, respectively.

Step-by-step explanation:

To find the wind force component F, we need to consider the forces acting on the skier.

(a) When the magnitude of the skier's velocity is constant, we know that the net force (including the wind force) acting on the skier is zero.

Therefore, the wind force component F would be zero as well.

(b) When the magnitude of the skier's velocity is increasing at a rate of 1.0 m/s^2, the net force acting on the skier is equal to the skier's mass multiplied by the acceleration.

The wind force component F can be calculated using Newton's second law, F = m * a.

In this case, F = 40 kg * 1.0 m/s^2 = 40 N.

(c) Similarly, when the magnitude of the skier's velocity is increasing at a rate of 2.0 m/s^2, the net force acting on the skier is 80 N (40 kg * 2.0 m/s^2), and the wind force component F would be 80 N as well.