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Dustin has a bag of marbles with 4 blue marbles, 4 white marbles, and 3 red marbles.

Find the following probabilities of Dustin drawing the given marbles from the bag if the first marble(s) is(are) not returned to the bag after they are drawn.

a) A Blue, then a red =

b) A red, then a white =

c) A Blue, then a Blue, then a Blue =

1 Answer

4 votes

Answer:

A.


(6)/(55)

B.


(6)/(55)

C.


(4)/(165)

Explanation:

Dustin has a bag of marbles with 4 blue marbles, 4 white marbles, and 3 red marbles. There are 11 marbles in total.

A. The probability that the first marble drawn is blue marble is


(4)/(11),

the probability that the second marble drawn is red marble is


(3)/(10)

The probability that the first marble drawn is blue and the second is red is


(4)/(11)\cdot (3)/(10)=(12)/(110)=(6)/(55)

B. The probability that the first marble drawn is red marble is


(3)/(11),

the probability that the second marble drawn is white marble is


(4)/(10)

The probability that the first marble drawn is red and the second is white is


(3)/(11)\cdot (4)/(10)=(12)/(110)=(6)/(55)

C. The probability that the first marble drawn is blue marble is


(4)/(11),

the probability that the second marble drawn is blue marble is


(3)/(10),

the probability that the third marble drawn is blue marble is


(2)/(9),

The probability that the first, second and third marbles drawn are blue is


(4)/(11)\cdot (3)/(10)\cdot (2)/(9)=(24)/(990)=(4)/(165)