Question

1. How many joules must be added to 10.0 g of water to raise its temperature from 10°C to

15°C?

Answer 1

To heat 10.0 g of water from 10°C to 15°C, we use the formula Q = mcΔT with the specific heat capacity of water (4.18 J/g°C), resulting in 209 J of energy required.

Step-by-step explanation:

To calculate how many joules must be added to 10.0 g of water to raise its temperature from 10°C to 15°C, we need to use the formula Q = mcΔT, where Q is the heat absorbed or released, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature.

The specific heat capacity of water is 4.18 J/g°C. Given the mass of the water m = 10.0 g and the temperature change ΔT = (15°C - 10°C) = 5°C, we can plug these values into the equation:

Q = (10.0 g) × (4.18 J/g°C) × (5°C)

Q = 209 Joules. Therefore, 209 J must be added to the water to raise its temperature by 5°C.

Answer 2

209.3 Joules require to raise the temperature from 10 °C to 15 °C.

Step-by-step explanation:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m × c × ΔT

Given data:

mass of water = 10 g

initial temperature T1= 10 °C

final temperature T2= 15 °C

temperature change =ΔT= T2-T1 = 15°C - 10°C = 5 °C

Energy or joules added to increase the temperature Q = ?

Solution:

We know that specific heat of water is 4.186 J/g .°C

Q = m × c × ΔT

Q = 10 g × 4.186 J/g .°C × 5 °C

Q = 209.3 J