Question

Problem Page Try Again Your answer is wrong. In addition to checking your math, check that you used the right data and DID NOT round any intermediate calculations. Gaseous butane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 51. g of butane is mixed with 150. g of oxygen. Calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction. Round your answer to significant digits.

Answer 1

The answer to your question is: 154.8 g of CO2

Step-by-step explanation:

Butane = 51 g

Oxygen = 150 g

Carbon dioxide = ?

Reaction

2C₄H₁₀ + 13 O₂ ⇒ 8CO₂ + 10H₂O

MW 2(58) 13(32) 8( 44) 10(18)

116g 416g 352g 180g

LImiting reactant

116 g of butane ----------------416 g oxygen

51 g ----------------- x

x = (51 x 416) / 116

x = 182.9 g of oxygen

The limiting reactant is butane and excess reactant is oxygen because we need 182.9 g and we have 416g.

Then we calculate the mass of Carbon dioxide with the mass of butane.

116 g of butane -------------------------- 352 g of CO2

51g -------------------------- x

x = (51 x 352) / 116

x = 154.8 g of CO2